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In an ap the sum of first n terms is 5n 2/2

WebJan 15, 2024 · If the sum of the first n terms of a series is 5n2 + 2n, then its second term is (A) 7 (B) 17 (C) 24 (D) 42 ... If the sum of the first n terms of a series is 5n 2 + 2n, then its second term is (A) 7 (B) 17 (C) 24 ... terms are in AP whose common difference is 2 and the last (2n + 1) asked Jan 18, 2024 in Binomial theorem by Ritik01 (48.4k ... WebThe sum of first n terms of an AP is (5n − n2). The nth term of the AP is (a) (5 − 2n) (b) (6 − 2n ... The sum of first n terms of an AP is (4 n 2 + 2 n) The nth term of this AP is (a) (6n-2) …

Sum Of The First n Terms Of An Arithmetic Progression

WebWe know that in an AP sum of the first n terms Sn = (n/2) {2a+ (n-1)d} and the nth term=a+ (n-1)d So (3n/2) {2a+ (3n-1)d} = (n/2) [2 {a+ (3n+1–1)d}+ (n-1)d] =>6a+9nd-3d = 2a+6nd+nd-d.. (This is after cancelling n/2 both sides =>4a+2nd-2d = 0 => 2a+nd-d = 0…. (1) The ratio of the first 2n termsis equal to the sum of the next 2n terms => WebThe sum of the first n term sofa an AP is ( 3 n 2 2 + 5 n 2). Find its nth term and the 25th term Advertisement Remove all ads Solution Let S denotes the sum of first n terms of the AP. ∴ s n = ( 3 n 2 2 + 5 n 2) ⇒ s n - 1 = 3 ( n - 1) 2 2 + 5 ( n - 1) 2 = 3 ( n 2 - 2 n + 1) 2 + 5 ( n - 1) 2 = 3 n 2 - n - 2 2 ∴ n th term pf the AP , a n imove shipping https://grupobcd.net

The sum of the first n terms of an AP is (5n^2/2 +3n/2

WebJul 25, 2024 · Mohammed Owais. 2 years ago. Its bcoz, (Ref=n/2) the sum of any 2 terms of an AP is divided by 2 gets it middle number. example, 3+6/2 is 4.5 which is the middle of these terms and if you … WebAug 28, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term. Advertisement Expert-Verified Answer 1282 people found it helpful Brainly User Let the … imove shelves

The sum of first n terms of an A.P. is 5n n2. Find the nth …

Category:Akrthmetic Progressions 115 EXERCISE 5.4 (Optional)* 1. Which term …

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In an ap the sum of first n terms is 5n 2/2

10] Find the sum of first

WebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... Web(11) Search the sum the first 20 terms of the numerical series in which 3 rl term is 7 also 7 in term is 2 more than three time its 3 rad term. Solution (12) Stylish an arithmetic series, which sum of first 11 conditions is 44 and one that of the next 11 terms is 55.

In an ap the sum of first n terms is 5n 2/2

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WebSolution Given that sum of the first n terms of an AP is 5n - n 2 Sn = 5n − n 2 First term, a 1 = S 1 = 5 (1) − (1) 2 = 5 − 1 = 4 Sum of first two terms = S 2 = 5 (2) − (2) 2 = 10 − 4 = 6. … WebThe sum of n terms of AP is the sum (addition) of first n terms of the arithmetic sequence. It is equal to n divided by 2 times the sum of twice the first term – ‘a’ and the product of the …

WebApr 10, 2024 · Sum of first n terms of an AP S n = n 2 [ 2 a + ( n − 1) d] Where a =1st term & d =common difference Or, S n = n 2 [ a + a n] If there are only n terms in an AP, then a n =l, l=last term We will put n=1, 2 in the sum formula and evaluate the first and second term of the A.P. Then we can easily derive the common difference. By putting all these in WebAn arithmetic progression or arithmetic sequence (AP) is a sequence of numbers such that the difference from any succeeding term to its preceding term remains constant throughout the sequence. The constant difference is called common difference of that arithmetic progression. For instance, the sequence 5, 7, 9, 11, 13, 15, . . . is an arithmetic progression …

WebJul 12, 2024 · Best answer Let Sn denotes the sum of first n terms of the AP. ∴ Sn = 5n - n2 ⇒ ⇒ Sn-1 = 5 (n - 1) - (n - 1)2 = 5n - 5 - n2 + 2n - 1 = 7n - n2 - 6 ∴ nth term of the AP, an = Sn … WebMar 31, 2024 · LeParfait Given: Sum of the first n-terms is 5n²/2 + 3n/2 To find: The 17th term of the A. P. Solution: Step 1. We find the sum of the first 17 terms. Sum of the first 17 terms is = 5 (17)²/2 + 3 (17)/2 = 5 (289)/2 + 51/2 = 1445/2 + 51/2 = 1496/2 = 748 Step 2. We find the sum of the first 16 terms. Sum of the first 16 terms is

WebApr 20, 2024 · The sum of the first n term of an AP,denoted by Sn is given by. Sn = n2 +8n. So. n th term of the series will be. tn = Sn −Sn−1 = n2 + 8n − ((n −1)2 +8(n − 1)) ⇒ tn = 2n …

WebApr 20, 2024 · The sum of the first n term of an AP,denoted by S_n is given by S_n=n^2+8n So n th term of the series will be t_n=S_n-S_(n-1)=n^2+8n-((n-1)^2+8(n-1)) =>t_n=2n-1+8=2n+7 Inserting n=1,2,3.... we get "For "n=1tot_1=2*1+7=9 "For "n=2tot_2=2*2+7=11 "For "n=3tot_3=2*3+7=13 Hence first term t_1=9 and common difference d=t_2-t_1=11-9=2 … imoves mental healthWebThe Sum of the First N Terms of an Ap in `((5n^2)/2 + (3n)/2)`.Find Its Nth Term and the 20th Term Of This Ap. CBSE English Medium Class 10 ... Important Solutions 4010. Question Bank Solutions 26519. Concept Notes & Videos 213. Time Tables 14. Syllabus. The Sum of the First N Terms of an Ap in `((5n^2)/2 + (3n)/2)`.Find Its Nth Term and the ... listowel lcbo hoursWebAP2: Sum of 1 term = 5x1+2 = 7 Ratio of the 1st term is 1:7. AP1: Sum of 2 term = 4x2–3 = 5. The second term = 5–1 = 4 AP2: Sum of 2 term = 5x2+2 = 12. The second term = 12 - 7 = 5 Ratio of the 2nd and subsequent terms is 4:5 So the ratio of the nth term of the two APs is 4:5 other than the first terms. 2 Quora User 4 y imoves mental health weekWebMar 22, 2024 · Transcript. Ex 9.2,13 If the sum of n terms of an A.P. is 3n2 + 5n and its mth term is 164, find the value of m. Let a1, a2, … an be the given A.P Given, Sum of n terms = 3n2 + 5n Sn = 3n2 + 5n Putting n = 1 in (1) S1 = 3 × 12 + 5 × 1 = 3 × 1 + 5 × 1 = 3 + 5 = 8 Sum of first 1 terms = First term ∴ First term = a1 = S1 = 8 Sn = 3n2 + 5n …(1) Putting n = 2 in … listowel memorial hospitalWebDec 19, 2024 · at n = 1, S 1 = 2 + 3 = 5 = first term at n = 2, S 2 = 2 (2) 2 + 3 (2) = 8 + 6 = 14 ≠ second term = sum of first two terms. ∴ second term = S 2 – S 1 = 14 – 5 = 9 ∴ d = a 2 – … imoves activeWebMar 23, 2024 · The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. 3. A ladder has rungs 25 cm apart. (see Fig. 5.7). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. listowel local area planWebGiven ratio of sum of n terms of two AP’s = (7n+1):(4n+27) Let’s consider the ratio these two AP’s mth terms as am : a’m →(2) Recall the nth term of AP formula, an = a + (n – 1)d Hence equation (2) becomes, am : a’m = a + (m – 1)d : a’ + (m – 1)d’ On multiplying by 2, we get am : a’m = [2a + 2(m – 1)d] : [2a’ + 2(m ... imoves brain break