WebbEquation of any plane passing through (-2, -2, 2) is a (x + 2) + b (y + 2) + c (z - 2) = 0 since it contains the line joining the points (1, 1, 1) and (1, -1, 2), it contains these points as well so that 3a + 3b - c = 0 and 3a + b + 0 = 0 on solving we get 1a = −3b = −6c and thus the equation of the plane is x+2− 3(y+ 2)− 6(z −2) = 0 or x−3y −6z … WebbWe seek the plane passing through the points A (1, 2, 5), B (3, − 7, 2), C (3 1 , 5, 6). (i) Define position vectors a, b, c to the respective points A, B, C. (ii) Construct displacement vectors, A B = b − a and BC = c − b. (iii) Use the cross product to find n, the vector normal to the plane containing A B and BC. (iv) What does the ...

Find the equation of parabola passing through the point (2,1) and ...

Webb11 feb. 2024 · closed Feb 17 by SukanyaYadav If the equation of the plane passing through the point (1,1,2) and perpendicular to the line x - 3y + 2z - 1 = 0 , 4x - y + z is Ax + By + Cz = 1, then 140 (C - B + A) is equal to _____. jee main 2024 1 Answer +1 vote answered Feb 11 by Rishendra (52.8k points) selected Feb 17 by SukanyaYadav Best answer WebbFinal answer. Transcribed image text: Find the equation of the plane passing through the line of intersection of the planes 2x +3y− z = 0 and x− 4y +2z = −5, and passing through the point (−2,0,−1. dvd records

We seek the plane passing through the points Chegg.com

WebbSince that plane passes through the point Q 1 = ( − 2, 3, 1) and is perpendicular to the direction ( 2, 1, 2). Its equation is 2 ( x + 2) + 1 ( y − 3) + 2 ( z − 1) = 0. Which simplifies to 2 x + y + 2 z = − 1 It will intersect the other line when ( 4 − 2 u) + ( 4 − u) + 2 ( − 4 − 2 u) = − 1, which is when u = 1 3. This gives us the point WebbThe plane passing through the points (1, 2, 1), (2, 1, 2) and parallel to the line, 2 x = 3 y, z = 1 also passes through the point: Q. The plane through the intersection of the planes x + y … WebbSubstituting the values of a, b, c, obtained in step 3, in equation (i) in step 1 to get the required plane. Example : Find the equation of the plane through the points A (2, 2, -1), B (3, 4, 2) and C (7, 0 , 6). Solution : The general equation of a plane passing through (2, 2, -1) is a (x – 2) + b (y – 2) + c (z + 1) = 0 …………….. (i) dvd red cliff